Question

Barium chloride is mixed with copper sulphate solution and white ppt. Is observed write the balance equation and write thier type

Answer 1

In solution, both are soluble and have dissociated into their component ions. When a barium ion collides with a sulfate ion it will form an insoluble compound. The barium sulfate precipitates to form a white solid.

BaCl2(aq) + CuSO4(aq) --> BaSO4(s) + CuCl2(aq)

The ionic equation is more descriptive:
Ba2+ + 2Cl- + Cu2+ + SO4^2- --> BaSO4(s) + Cu2+ + 2Cl-

The net ionic equation tells us that barium ions will always react with sulfate ions to make an insoluble product.
Ba2+ + SO4^2- --> BaSO4(s)

Answer 2

Answer: The balanced chemical equation is written below and this is a type of double displacement reaction.

Explanation:

When barium chloride reacts with copper sulfate, a white precipitate of barium sulfate is observed.

The chemical equation for the reaction of barium chloride and copper sulfate follows:

$BaCl_2(aq.)+CuSO_4(aq.)\rightarrow BaSO_4(s)+CuCl_2(aq.)$

By Stoichiometry of the reaction:

1 mole of barium chloride reacts with 1 mole of copper sulfate to produce 1 mole of white precipitate of barium sulfate and 1 mole of copper (II) chloride.

The above reaction is double displacement reaction because here, exchange of ions takes place.

Hence, the balanced chemical equation is written above and this is a type of double displacement reaction.