Barium Chloride reacts with Aluminium Sulphate to give aluminium Chloride and a precipitate of Barium sulphate
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3BaCl2 + Al2(SO4)3 = 2AlCl3 + 3BaSO4
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Answer:
3BaCl2(s) + Al2(SO4)3(s) ➝ 3BaSO4 + 2Al2Cl3(s)
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