Question

Barium chloride reacts with Sodium sulphate to form a white precipitate of Barium sulphate and Sodium chloride. In an experiment, 127g of Barium chloride reacted with 142g of Sodium sulphate to form 152g of Barium sulphate. What will be the mass of Sodium chloride formed?

Answer 1

Answer:

answer is 117g of sodium cholride

Explanation:

BARIUM CHOLRIDE- 127g

SODIUM. SULPHATE-142g

Barium sulphate-152g

Sol:-barium cholride+sodium sulphate -barium sulphate=sodium cholride

127+142-152=117g