BARRIERS ARE PLACE AROUND TREES. FOR EACH INCH OF TRUNK DIAMETER, THE PROTECTION ZONE SHOULD HAVE A RADIUS OF 4/3 FEET. FIND THE AREA OF THE ZONE FOR A TREE WITH A TRUNK CIRCUMFERENCE OF 63 INCHES
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Solution:-
Circumference = 63 inches
2πr = 63
2*22/7*r = 63
r = (63*7)/44
r = 441/44
r = 10 inches (Approx)
Radius of the Protection Zone = 4/3 feet = (4*12)/3 = 16 inches
Now, the radius of the protection zone will be = 10 + 16
= 26 inches
Area of the whole zone = πr²
= 22/7*26*26
= 14872/7
Area of the zone = 2124.57 sq inches.
Answer
Circumference = 63 inches
2πr = 63
2*22/7*r = 63
r = (63*7)/44
r = 441/44
r = 10 inches (Approx)
Radius of the Protection Zone = 4/3 feet = (4*12)/3 = 16 inches
Now, the radius of the protection zone will be = 10 + 16
= 26 inches
Area of the whole zone = πr²
= 22/7*26*26
= 14872/7
Area of the zone = 2124.57 sq inches.
Answer
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