Barun lives in Jaipur in Vaishali. Satellite image of his colony is shown in given figure. In this view, his house is pointed out by a flag, which is situated at the point of intersection of x and y - axes. If he goes 2 cm east and 3 cm north from the house, then he reaches to a grocery store, If he goes 4 cm west and 6 cm south from the house, then he reaches to his office. If he goes 6 cm east and 8 cm south from the house, then he reaches to a food court. If he goes 6 cm west and 8 cm north from the house, he reaches to a his kid’s school. Based on the above information, answer the following questions (i) What is the distance between grocery store and food court?
Answers
Answer:
1)a root 137 CM
2) a 10 CM
3) a 2:1
4) a 1:1
5) d quadilateral
Given:
Barun lives in Jaipur
His house is the point of intersection of two axes.
From his house, 2 cm east and 3 cm north is a grocery store.
From his house, 4 cm west and 6 cm south is his office.
From his house, 6 cm east and 8 cm south is the food court.
From his house, 6 cm west and 8 cm north is the kid's school.
To find:
Distance between the grocery store and food court
Solution:
Consider the house is at origin the coordinates of the grocery store, office, food court, and school are respectively are (2,3), (-4,-6), (6,-8) and (-6,8).
Distance between two points = √(x2-x1)^2 + (y2-y1)^2
Distance between the grocery store and food court = √(6-2)^2 + (-8-3)^2
= √(4)^2 + (-11)^2
= √ 16 + 121
= √137
Hence, the distance between the grocery store and the food court is √137 units.