Question

Base = 4 cm , Perpendicular = 3 cm. Find the value of all trigonometry ratio

Answer 1

Hii friend,


Base (b) = 4 cm

Perpendicular (p) = 3 cm

THEREFORE,

H = ✓(p)² + (b)²

H = ✓(3)² + (4)²

H = ✓9+16

H = ✓25 = 5.

THEREFORE,

Sin@ = P/H = 3/5

Cosec@ = H/P = 5/3

Cos@ = B/H = 4/5

Sec@ = H/B = 5/4

Tan@ = P/B = 3/4

Cot@ = B/P = 4/3..

HOPE IT WILL HELP YOU.... :-)

Answer 2

Hey there Friend ☺

Here is your answer
-------------------------------
By using Pythagoras Theorem for finding Hypotenuse

H²=B²+P²
=4²+3²
=16+9=25
H= 5 cm

Now applying Trigonometric ratios
$\sin(x) = \frac{p}{h} = \frac{3}{5} \\ \cos(x) = \frac{b}{h} = \frac{4}{5} \\ \tan(x) = \frac{p}{b} = \frac{3}{4} \\ \cot(x) = \frac{b}{p} = \frac{4}{3} \\ \sec(x) = \frac{h}{b} = \frac{5}{4} \\ \csc(x) = \frac{h}{p} = \frac{5}{3}$
These are the six ratios

Let me inform you some further details about these

$\frac{ \sin }{ \cos} = \tan \\ \frac{1}{ \csc } = \sin \\ \frac{1}{ \sec} = \cos \\ \frac{ \cos }{ \sin} = \cot \\ \frac{1}{ \cot } = \tan$
Hope it helped you