Question

Base
8. Base of a triangle is 9 and height is 5
of another twiangle 10 and height is 6
the ratio of coueas of these triangle​

Answer 1

Step-by-step explanation:

Area of first triangle =

\begin{lgathered}\frac{1}{2} \times 9 \times 5 \\ {cm}^{2}\end{lgathered}

2

1

×9×5

cm

2

Area of second triangle =

\begin{lgathered}\frac{1}{2} \times 10 \times 6 \: {cm}^{2} \\ = 30 {cm}^{2}\end{lgathered}

2

1

×10×6cm

2

=30cm

2

Ratio =

\begin{lgathered}\frac{ \frac{1}{2} \times 9 \times 5}{30} \\ = \frac{3}{4}\end{lgathered}

30

2

1

×9×5

=

4

3