Question

base AB=5.4 cm, angleB= 45 and AC+BC=9 cm
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Answer 1

$\huge\underbrace\mathfrak \red{ANSWER }$

1. Draw of 5.4cm

2. Construct angle at 45°at A.

3. With radius as 9cm at A , cut an arc along the 45° line and mark the point as D . Join B-D.

4. Draw a perpendicular bisector of BDand mark its intersection with AD as C .

5. Join AC .

6. ABC is the required triangle.

HOPE SO IT WILL HELP......✌

Answer 2

Step-by-step explanation:

we shld construct this..

steps :

Draw AB of 5.4 cm.

Draw AB of 5.4 cm.2. Construct angle 45

Draw AB of 5.4 cm.2. Construct angle 45 ∘

Draw AB of 5.4 cm.2. Construct angle 45 ∘ at A.

Draw AB of 5.4 cm.2. Construct angle 45 ∘ at A.3. With radius as 9 cm at A, cut an arc along the 45

Draw AB of 5.4 cm.2. Construct angle 45 ∘ at A.3. With radius as 9 cm at A, cut an arc along the 45 ∘

Draw AB of 5.4 cm.2. Construct angle 45 ∘ at A.3. With radius as 9 cm at A, cut an arc along the 45 ∘ line and mark the point as D. Join B−D.

Draw AB of 5.4 cm.2. Construct angle 45 ∘ at A.3. With radius as 9 cm at A, cut an arc along the 45 ∘ line and mark the point as D. Join B−D.4. Draw a perpendicular bisector of BD and mark its intersection with AD as C.

Draw AB of 5.4 cm.2. Construct angle 45 ∘ at A.3. With radius as 9 cm at A, cut an arc along the 45 ∘ line and mark the point as D. Join B−D.4. Draw a perpendicular bisector of BD and mark its intersection with AD as C.5. Join AC.

Draw AB of 5.4 cm.2. Construct angle 45 ∘ at A.3. With radius as 9 cm at A, cut an arc along the 45 ∘ line and mark the point as D. Join B−D.4. Draw a perpendicular bisector of BD and mark its intersection with AD as C.5. Join AC.6. ABC is the required triangle.