Question

Base area of a square pyramid is 256 square centimetres and the length of its lateral edge is 17 centimetres calculate its slant height

Answer 1

Answer:

here we apply pythagoras theorem to find the height

first of all we have to draw a perpendicular line from top of the pyramid to the center of the base square wher both diagonals of square meet as a result we get a right angled triangle

second step:

Area of square = length× width

= 16×16

=256

so

length of each side of square =16

as i said above in step 1 that i draw a perpendicular line in this case the base of right angled triangle is

base=8

slant height or lateral edge=hypotenuse=17

step 3:

applying pythagoras theorem

(hyp)square=(base)square+(perp)square

here perpendicular=height of pyramid

so

putting the values

(17×17)=(8×8)+(height)square

289=64+(height)square

or (height) square=289-64

=225

squaring on both side

height=15