Question

base of a rectangle is 9 and height is 5. base of another triangle is 10 and height is 6. find the ratio of area's of these triangles​

Answer 1

HELLO DEAR FRIEND

GIVEN BASE OF RECTANGLE = 9CM

HEIGHT OF RECTANGLE. = 5CM

BASE OF TRIANGLE = 10CM

HEIGHT OF TRIANGLE = 6CM

RATIO OF AREAS =

= $\large{ \frac{ \large{area \: of \: rectangle}}{ \large{area \: of \: triangle}} }$

= $\large{ \frac{ \large{(9 \times 5)cm}}{ \large{ (\frac{1}{2} \times 10 \times 6)}cm} }$

= $\large{ \frac{ \large{45}}{ \large{30}}}$

= $\large{ \frac{ \large{3}}{ \large{2}}}$

$= \: \: \huge \boxed{3:2} \small{ans}$

HOPE IT HELPS YOU DEAR FRIEND THANKS

Answer 2

Answer:

Let ABC and PQR be two right triangles with AB ⊥ BC and PQ ⊥ QR.

Given:

BC = 9, AB = 5, PQ = 6 and QR = 10.

∴A(△ABC)/A(△PQR)

=AB×BC/PQ×QR

=5×9/6×10

=3/4