Question

Base of a triange is 9 and height is 5. Base of the another triangle is 10 and height is 6. Find the ratio of areas of these triangle.​

Answer 1

Answer:

$\boxed{\orange{\bold{=3:4}}}$

Step-by-step explanation

TRIANGLE 1

Base = 9 units

height=5 units

area of a triangle is half the product of base and height.

mathematically:-

$\dfrac{1}{2}*9*5=2.5*9 unit^2$

TRIANGLE 2

Base =10 unit

height=6 units

Area of this triangle is :-

$\dfrac{1}{2}*10*6=5*6=30$

RATIO OF AREAS

Ratio is equal to :-

$\dfrac{2.5*9}{30}\\ \\ \\ \\=\dfrac{3}{4}\\ \\ \\ \\=3:4$

Answer 2

Answer:

Let ABC and PQR be two right triangles with AB ⊥ BC and PQ ⊥ QR.

Given:

BC = 9, AB = 5, PQ = 6 and QR = 10.

∴A(△ABC)/A(△PQR)

=AB×BC/PQ×QR

=5×9/6×10

=3/4