Question

Base of a triangle is 10 cm and height is 4cm. Base of another triangle is 12 cm and height is 5.cm Find the ratio of areas of these triangles.

1️⃣ 2/3
2️⃣ 3/2
3️⃣ 40/12
4️⃣ 10/60​

Answer 1

Answer:

Area of 1st triangle =1/2 into B into H

1/2 into 10 into 4 = 5 into 4 = 20

Area of 2nd triangle = 1/2 into 12 into 5 = 6 into 5 = 30

Ratio of both triangles = Area of 1st triangle /Area of second triangle

20/30 = 2/3

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Answer 2

Solution :-

we know that,

• Area of a ∆ = (1/2) * Base * Perpendicular height .

So, given that,

→ ∆1 Base = 10 cm

→ ∆1 perpendicular height = 4 cm .

then,

→ ∆1 Area = (1/2) * Base * Perpendicular height = (1/2) * 10 * 4 = 20 cm²

similarly,

→ ∆2 Base = 12 cm

→ ∆2 perpendicular height = 5 cm .

then,

→ ∆2 Area = (1/2) * Base * Perpendicular height = (1/2) * 12 * 5 = 30 cm²

therefore,

→ Area ∆1 : Area ∆2 = 20 cm² : 30 cm²

→ Area ∆1 : Area ∆2 = 20 : 30

→ Area ∆1 : Area ∆2 = 2 * 10 : 3 * 10

→ Area ∆1 : Area ∆2 = 2 : 3 (1) (Ans.)

Hence, the ratio of areas of these triangles is equal to 2 : 3 .

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