Question

base of a triangle is 12cm and height is 7cm base of another triangle is 14cm and height is 10cm find the ratio of areas of these triangles​

Answer 1

using the formula 1/2*base*hight

base=12 ,height= 7

1/2*12/*7

42

another triangle

base=14

height=10

1/2*14*10

70

ratio

42:70

21:35

3:5

the ratio =3:5

mark as brailiest

Answer 2

Given:

Two triangles.

• The first triangle - base is 12 cm and the height is 7 cm.
• The second triangle - base is 14 cm and the height is 10 cm.

The formula to find the area of the triangle is,

$=\boxed{\frac{1}{2}\times base \times height}\ unit\ sq.$

Now,

• Area of the first triangle,

$=\boxed{\frac{1}{2}\times base \times height}\ unit\ sq.$

$= \frac{1}{2}\times 12\times 7$

=  42 cm sq.

And

• Area of the second triangle,

$=\boxed{\frac{1}{2}\times base \times height}\ unit\ sq.$

$=\frac{1}{2}\times 14\times 10$

= 70 cm sq.

Now, Ratio of the first triangle and the second triangle is

$\bf =\frac{Area\ of\ the\ first\ triangle}{Area\ of\ the\ second\ triangle}$

$= \bf \frac{42}{70}$

$\bf = \frac{3}{5}$

Hence,

The ratio of the first triangle to the second triangle is 3:5