Math, asked by maithiliparab06, 1 month ago

Base of a triangle is 15 and height is 6. Base of another triangle is 12 and height is 5. Then the ratio of the areas of these triangles are __________.​

Answers

Answered by TwilightShine
5

Answer -

  • The ratio of the area of the two triangles = 3 : 2.

To find -

  • The ratio of the area of the two triangles.

Step-by-step explanation -

  • Here, the base and height of two triangles are given to us. We have to find the ratio of their areas.

Used formula -

 \bigstar \: \underline{\boxed{\sf Area_{(triangle)} = \dfrac{1}{2} \times Base \times Height}}

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Finding the area of the first triangle -

  • Here, the base of the triangle = 15 units and it's height = 6 units.

\longrightarrow \:  \dfrac{1}{2}  \times 15 \times 6

 \longrightarrow \:  \dfrac{1}{2}  \times 90

 \longrightarrow \:   \cancel{\dfrac{90}{2}}

 \rm \longrightarrow \: 45 \: sq.units

----------------------------------------------

Finding the area of the second triangle -

  • Here, the base of the triangle = 12 units and it's height = 5 units.

 \longrightarrow \:  \dfrac{1}{2}  \times 12 \times 5

 \longrightarrow \:  \dfrac{1}{2}  \times 60

 \longrightarrow \:   \cancel{\dfrac{60}{2}}

 \rm \longrightarrow \: 30 \: sq.units

---------------------------------------------

Finding the ratio of the area of the two triangles -

 \bf \longmapsto \cancel{\dfrac{45}{30}}

 \bf \longmapsto  \dfrac{3}{2}

  \bf\longmapsto 3 : 2

 \\

Hence -

  • The ratio of the areas of these two triangles = 3 : 2.

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Answered by MathCracker
14

Question :-

Base of a triangle is 15 and height is 6. Base of another triangle is 12 and height is 5. Then the ratio of the areas of these triangles are __________.

Solution :-

Given :

By first triangle,

  • Base = 15
  • Height = 6

By second triangle,

  • Base = 12
  • Height = 5

Need to find :

  • Ratio of both triangle

Required Formula :

{\boxed{\rm{\red{Area \: of \: triangle = \frac{1}{2} × base × height}}}}

Area of first triangle

\sf:\longmapsto{A= \frac{1}{2} \times 15 \times 6  } \\  \\ \sf:\longmapsto{A= \frac{1}{2} \times 90 } \:  \:  \:  \:  \:  \\  \\ \sf:\longmapsto{A=45} \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:

Area of first triangle is 45.

Area of second triangle

\sf:\longmapsto{A= \frac{1}{2}  \times 12 \times 5} \\  \\ \sf:\longmapsto{A= \frac{1}{2}  \times 60} \:  \:  \:  \:  \:  \:  \\  \\ \sf:\longmapsto{A=30} \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:

Area of second triangle is 30.

Ratio of both triangle

\sf:\longmapsto{ \cancel \frac{45}{30} }   \:  \:  \: \\  \\ \sf:\longmapsto{ \frac{3}{2} } \: \:  \:  \:  \:    \\  \\ \sf:\longmapsto{3 :2 }

The ratio of both triangle is 3:2.

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