Question

Base of a triangle is 6 and height is 4. Base of another triangle is 8 and height is 12. Find the ratio of areas of these triangles? *​

Answer 1

Answer :

›»› The area of these two triangles are 1 : 4.

Given :

• Base of a triangle is 6 and height is 4.
• Base of another triangle is 8 and height is 12.

To Find :

• The ratio of areas of these triangles?

Solution :

Let,

The triangle having Base of a triangle is 6 and height is 4 be first triangle.

And, the traingle having Base of triangle is 8 and height is 12 be second triangle.

⋆ According to the given question,

→ Area of first triangle = ½ * b * h

→ Area of first triangle = ½ * 6 * 4

→ Area of first triangle = 1 * 3 * 4

→ Area of first triangle = 3 * 4

→ Area of first triangle = 12 cm²

Similarly,

→ Area of second triangle = ½ * b * h

→ Area of second triangle = ½ * 8 * 12

→ Area of second triangle = 1 * 4 * 12

→ Area of second triangle = 4 * 12

→ Area of second triangle = 48 cm²

Now, The ratio of areas of these two triangles :-

→ Area of first triangle : Area of second triangle

→ 12 : 48

→ 1 : 4

║Hence, the area of these two triangles are 1 : 4.║

Answer 2

$\huge\bold{\underline{Answer}}$

The areas of triangles are in ratio 1:4

________________________________

Formula for area of right angled triangle:

$\large\boxed{Area = 1/2 × base \times height}$

⇛For First triangle:

• Base = 6
• Height = 4

Area = 1/2 × 6 × 4

= 12

⇛For second triangle :

• Base = 8
• Height = 12

Area = 1/2 × 8 × 12

= 48

Ratios of areas of triangles :

=12/48

=1/4

1:4 is the answer