Question

base of a triangle is 7 and height is 8. Base of another triangle is 9 and height is 12 find the ratio areas of these two triangles​

Answer 1

Answer:

area of triangle = 1/2 *b*h

so

$\frac{area \: of \: \: first }{area \: of \: second} = \frac{ \frac{1}{2} \times 7 \times 8 }{ \frac{1}{2} \times 9 \times 12} \\ = \frac{56}{108} = \frac{14}{27}$

Answer 2

Answer:

3:4

Step-by-step explanation:

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Here's your answer.. ⬇⬇

♦ Given :- Let The triangle be ∆ABC and ∆PQR.

In ∆ABC,

Base of ∆ABC is BC = 9cm

Altitude of ∆ABC is AE = 5cm

In ∆PQR,

Base is QR = 10cm

Altitude is PM = 6cm

♦ To Find :- Ratio of Area of ∆ABC and ∆PQR

♦ Solution :-



Hence, Ratio of Area of ∆ABC to ∆PQR is 3:4

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