Math, asked by nilimapd2012, 9 months ago

Base of a triangle is 9 & height is 5.Base of a another triangle is 10 & height is 6. Find the ratio of areas of these triangles.​

Answers

Answered by physicssirAtharv
0

Step-by-step explanation:

area of first triangle will be 22.5 and area of second triangle will be 30

then ratio of this two triangle = 22.5/30

solve it till it get si ply.. ur ratio will be there..

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Answered by Isighting12
0

Answer:

Base of the triangle 1 =  b' = 9 units

Height of triangle 1 = h' = 5 units

Base of the triangle 2 = b =10 units

Height of triangle 2 = h = 6 units

As we know the area of a triangle is    \frac{1}{2} (B)(H)

Thus area of triangle 1 = \frac{1}{2} (b')(h')

= \frac{1}{2} (9)(5)

= \frac{45}{2}

Also the are of triangle 2 =\frac{1}{2} (b)(h)

= \frac{1}{2} (10)(6)

= \frac{30}{2}

= 15

Ratio = \frac{area of triangle 1}{area of triangle 2}

= \frac{\frac{45}{2} }{15}

= \frac{45}{2 * 15}

= \frac{3}{2}

Therefore ratio is 3:2

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