Question

Base of a triangle is 9 & height is 5 base of another triangle is 8 & height is 4 what is the ratio of their areas

Answer 1

First triangle:

We have,

Base,b = 9 and Height,h = 5

We know that,

Area of triangle = 1/2 × b × h

= 1/2 × 9 × 5

= 45/2

= 22.5

Second triangle:

We have,

Base,b = 8 and Height, h = 4

We know that,

Area of triangle = 1/2 × b × h

= 1/2 × 8 × 4

= 32/2

= 16

Now,

Ratio of areas = 1st triangle /2nd triangle

= 22.5 / 16

= 225 / 160

= 45:32

Thus, Required ratio is 45:32.

Answer 2

Answer:

45:32

Step-by-step explanation:

Given :

Base of first triangle = 9

Height of first triangle = 5

Base of second triangle = 8

Height of second triangle = 4

To find:

Ratio of areas of both triangles

Area of a triangle = 1/2 × b × h

Where,

b = base

h = height

Substituting the values for area of first triangle, we get :

Area of first triangle = 1/2 × 9 × 5

Area of first triangle = 9 × 2.5

Area of first triangle = 22.5

Similarly,

Area of second triangle = 1/2 × 8 × 4

Area of second triangle = 16

Ratio = 22.5:16

Ratio should be in the form of whole numbers, so :

22.5 × 2 : 16 × 2

45 : 32