Question

Base of a triangle is 9 and height is 5. Base of another triangle is 10 and height is 6. Find the ratio of areas of these triangles.

Answer 1

Answer:

Step-by-step explanation:

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♦ Given :- Let The triangle be ∆ABC and ∆PQR.

In ∆ABC,

Base of ∆ABC is BC = 9 cm

Altitude of ∆ABC is AE = 5 cm

In ∆PQR,

Base is QR = 10 cm

Altitude is PM = 6 cm

♦ To Find :- Ratio of Area of ∆ABC and ∆PQR

♦ Solution :-

=area of abc / area of pqr

=1/2 * ac * bc / 1/2 * pm * qr

=1/2 * 5 * 9 / 1/2 * 6 * 10

=3/4

Hence, Ratio of Area of ∆ABC to ∆PQR is 3:4

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Answer 2

Answer:

Let ABC and PQR be two right triangles with AB ⊥ BC and PQ ⊥ QR.

Given:

BC = 9, AB = 5, PQ = 6 and QR = 10.

∴A(△ABC)/A(△PQR)

=AB×BC/PQ×QR

=5×9/6×10

=3/4