Math, asked by vinaykamble10a, 7 months ago

Base of a triangle is 9 and height is 5. Base of another triangle is 10 and height is 6. Find the ratio of the areas of these trianlge. *​

Answers

Answered by prince5132
25

GIVEN :-

  • Base of 1st triangle = 9 units.
  • Height of 1st triangle = 5 units
  • Base of 2nd triangle = 10 units.
  • Height of 2nd triangle = 6 units

TO FIND :-

  • Ratio of area of both triangles.

SOLUTION :-

Area For First Triangle,

 \star \:  \sf \: base \:(b)  = 9 \: unit \\  \star \sf \: height \: (h) \:  = 5 \: units \\  \\  \sf \to \: area \: ( 1st \triangle) =  \dfrac{1}{2}  \times b \times h \\  \\  \to \sf \:  \dfrac{1}{2}  \times 9 \times 5 \\  \\  \to \boxed{ \red{ \bf \: area \: (1st \triangle) =  \dfrac{45}{2}..........(1) }}

Area of second triangle,

 \star \:  \sf \: base \:(b)  = 10\: unit \\  \star \sf \: height \: (h) \:  = 6 \: units \\  \\  \sf \to \: area \: ( 2nd \triangle) =  \dfrac{1}{2}  \times b \times h \\  \\  \to \sf \:  \dfrac{1}{ \cancel2}  \times 10 \times  \cancel{6 }\\  \\  \to \boxed{ \red{ \bf \: area \: (2nd \triangle) =  30 \: ..........(1) }}

According to the Question :-

 \huge { \boxed{{\purple{ \implies \: (1) \div (2)}}}} \\  \\  \implies \:  \sf \left(\dfrac{ \dfrac{45}{2} }{30} \right) \\  \\  \implies  \sf \:  \dfrac{45}{2}  \times  \dfrac{1}{30}  \\  \\  \implies \sf \:  \dfrac{ \cancel{45}}{ \cancel{60}} \\  \\  \implies \sf \:  \dfrac{3}{4}  \\  \\  \implies \boxed{ \red{ \bf \:ratio \: of \: both \:  \triangle = 3 \ratio 4 }}

Hence the ratio of both triangle is 3 : 4.

Answered by Anonymous
34

\huge\boxed{\fcolorbox{red}{red}{Your Answer}}

given,

base of 1st △= 9

height of 1st △= 5

base of 2nd △= 10

height of 2nd △= 6

to find,

ratio of the areas of these triangle.

we need to :-

1st:

Area = ½ (b × h) Square Units.

Area of 1st △ ½ (b × h) Square Units.

Area of 1st △ ½ (9 × 5) Square Units.

Area of 1st △ ½ (45) Square Units.

hence, area = 22 1⁄2

2nd:

Area = ½ (b × h) Square Units.

Area of 1st △ ½ (b × h) Square Units.

Area of 1st △ ½ (10 × 6) Square Units.

Area of 1st △ ½ (60) Square Units.

hence, area = 30

therefore,

the ratio of the areas of these triangle = 22 1⁄2:30

= 11 1⁄2:15

{\fcolorbox{red}{purple}{mark \: as \: brainliest \: answer}}

\boxed{\fcolorbox{red}{pink}{by \: prashansa2008}}

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