Question

Base of a triangle is 9 and height is 5. Base of another triangle is 10 and height is 6 find A1 : A2.​

Answer 1

A_1 : A_2 = 3:4

Step-by-step explanation:

Given :-

• Base of first triangle = 9 unit .
• Base of another triangle = 10 unit .
• Height of first triangle = 5 unit .
• Height of another triangle = 6 unit .

To find :-

• The ratio of areas of the first triangle and second triangle .

Formula used :-

• Area of triangle = ½ base × height .

Solution :-

$\sf\dfrac{A_1}{A_2 } = \dfrac{ \dfrac{1}{2} \times base_ {{1}^{st} triangle}\times height_ {{1}^{st}triangle} }{ \dfrac{1}{2} \times base_ {{2}^{nd} triangle}\times height_ {{2}^{nd}triangle}} \\ \\ \sf \: \dfrac{A_1}{A_2 } = \dfrac{ \dfrac{1}{2} \times 9 \times 5}{ \dfrac{1}{2} \times 10 \times 6} \\ \\ \sf \: \dfrac{A_1}{A_2 } = \dfrac{ \dfrac{45}{2} }{30} \\ \\ \sf \: \dfrac{A_1}{A_2 } = \dfrac{45}{2 \times 30} \\ \\ \sf \: \dfrac{A_1}{A_2 } = \dfrac{45}{60} \\ \\ \sf \: \dfrac{A_1}{A_2 } = \dfrac{3}{4}$

Hence, A_1 : A_2 = 3 : 4