Question

Base of a triangle is 9 and height is 5 , Base of another triangle is 15 and height is 6. Find the ratio of areas of these triangles.


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Answer 1

=

Area(△PQR)

Area(△ABC)

=

2

1

×PM×QR

2

1

×AC×BC

=

2

1

×6×10

2

1

×5×9

=

4

3

Hence, Ratio of Area of △ABC:Area of △PQR=3:4

Answer 2

Answer:

Let ABC and PQR be two right triangles with AB ⊥ BC and PQ ⊥ QR.

Given: BC = 9, AB = 5, PQ = 6 and QR = 10.

Area (∆ABC) / Area (∆PQR)

= ½ AC X BC / ½ PQ X QR

= ½ X 5 X 9 / ½ X 6 X 10

= ¾

Hence, Ratio of Area of △ABC : Area of △PQR = 3: 4.

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