Math, asked by Anonymous, 4 months ago

Base of a triangle is 9 and height is 5 , Base of another triangle is 15 and height is 6. Find the ratio of areas of these triangles​

Answers

Answered by Anonymous
4

Answer:

22.5 /45 = 22.5 x 10 / 45 x 10 = 225 / 450 = 45/90 = 1/2

So the ratio is 1:2

Answered by Anonymous
133

\huge\underline\bold\red{Answer:-}

\large\underline\bold\blue{Given:-}

In ∆ABC

Base  and height = 9 and 5

In ∆PQR

Base  and height = 15 and 6

\large\underline\bold\green{To\:prove:-}

The Ratio of areas of these triangles.

\large\underline\bold\orange{Formula\:to\:be\:used}

\implies Area of triangle, A = 1/2 × b × h

\large\underline\bold\pink{solution:-}

Let the triangles be ∆ABC and ∆PQR.

Area of triangle, A = 1/2 × l × b

\dashrightarrow Area of ∆ABC/Area of ∆PQR.

\dashrightarrow 1/2 × b × h/1/2 × b × h

\dashrightarrow(1/2 × 5 × 9)/(1/2 × 15 × 6)

\dashrightarrow 1/2

Hence, the ratio of Area of ∆ABC : Area of ∆PQR IS 1 : 2.

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