Question

Base of a triangle is 9 and height is 5 , Base of another triangle is 15 and height is 6. Find the ratio of areas of these triangles​

Answer 1

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$\huge\underline\bold\red{Answer:-}$

$\large\underline\bold\blue{Given:-}$

In ∆ABC

Base  and height = 9 and 5

In ∆PQR

Base  and height = 15 and 6

$\large\underline\bold\green{To\:prove:-}$

The Ratio of areas of these triangles.

$\large\underline\bold\orange{Formula\:to\:be\:used}$

$\implies$ Area of triangle, A = 1/2 × b × h

$\large\underline\bold\pink{solution:-}$

Let the triangles be ∆ABC and ∆PQR.

Area of triangle, A = 1/2 × l × b

$\dashrightarrow$ Area of ∆ABC/Area of ∆PQR.

$\dashrightarrow$ 1/2 × b × h/1/2 × b × h

$\dashrightarrow$(1/2 × 5 × 9)/(1/2 × 15 × 6)

$\dashrightarrow$ 1/2

Hence, the ratio of Area of ∆ABC : Area of ∆PQR IS 1 : 2.

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