Question

base of a triangle is 9 and height is 5.base of another triangle is 10 and height is 6.find the ratio of areas of these triangles.
solve this properly and write
Given:-...
To find:-...
solution:-...​

Answer 1

Answer:

Ratio of the areas of these triangles = 3:4

Step-by-step explanation:

Given :

Base of the first triangle = 9 cm

Height of the first triangle = 5 cm

Base of the another triangle = 10 cm

Height of the another triangle = 6 cm

(Taken , "cm" because there is not given any measurement symbol)

To find :

The ratio of the area of these triangles

Taken :

First to find the area of the triangle use this formula -:

$\boxed{\sf{A=\dfrac{1}{2}\times b\times h}}$

Where,

A = Area of the triangle

b = Base

h = Height

And to find the ratio use this formula -:

$\boxed{\sf{R=\dfrac{A_{first\: triangle}}{A_{second\:triangle}}}}$

Where,

R = Ratio

Solution :

$:\Rightarrow\sf{R=\dfrac{\dfrac{1}{\cancel{2}}\times\cancel{9cm}\times5cm}{\dfrac{1}{\cancel{2}}\times\cancel{10cm}\times6cm}}$

$:\Rightarrow\sf{R=\dfrac{4.5cm\times5cm}{5cm\times6cm}}$

$:\Rightarrow\sf{R=\dfrac{22.5{cm}^{2}}{30{cm}^{2}}}$

Cancel the point and add a 0 at ones place of 30 cm² .

$:\Rightarrow\sf{R=\cancel{\dfrac{225{cm}^{2}}{300{cm}^{2}}}}$

$:\Rightarrow\sf{R=\dfrac{3}{4}}$

$:\Rightarrow\sf{R=3:4}$

So , the ratio of the area of these triangles are 3:4 .

Answer 2

correct answer for your question