Question

Base of a triangle is 9 and height is 5.Base of another triangle is 10 and height is 6.Find the ratio of areas of these triangle

Answer 1

Hii There!!!

Let two triangles be ∆1 &∆2 respectively

Since, area of a triangle=1/2×base×height.

=)Ar(∆1)=> 1/2×9×5 =) 45/2cm2

=)Ar(∆2) => 1/2×10×6=) 60/2=) 30cm2

Hence, Ratio of both the triangles.
or ar ∆1 : ar∆2

=) 45/2 ÷30 =) 45/2×1/30=) 3/4
=) 3:4

Hence , the ratio of area of triangles is 3:4

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Answer 2

Answer:

Let ABC and PQR be two right triangles with AB ⊥ BC and PQ ⊥ QR.

Given:

BC = 9, AB = 5, PQ = 6 and QR = 10.

∴A(△ABC)/A(△PQR)

=AB×BC/PQ×QR

=5×9/6×10

=3/4