Question

Base of a triangle is 9 and height is 5. Base of another triangle is 10 and height is 6. Find the Ratio of areas of these triangles

Answer 1

The base of the first triangle is 9 units and its height is 5 units.
Therefore the area of the first triangle = (1/2)(base×height)
                                                             =(1/2)(9)(5)=45/2 sq.units.
The base of the second triangle is 10 units and its height is 6 units.
∴The Area of the second triangle = (1/2)(base×height)
                                                     =(1/2)(10)(6)=30 sq.units.
Hence,the ratios of areas of the triangles=(45/2):(30)=3:4

Answer 2

$\large{\mathfrak{HELLO \: \: DEAR,}}$

$\mathit{WE \: KNOW \: \: THAT:- AREA \: \: OF \: \: TRIANGLE = \frac{1}{2}(base * height)}$


$\mathbf{\underline{now }} \\ \\ \mathit{IN \: \: CASE ( 1 ),}$


$BASE = 9 \: UNIT , \: \: \: HEIGHT = 5UNIT \\ \\ \mathit{AREA \: \: OF \: \: TRIANGLE = \frac{1}{2} ( 9 * 5)}\\ \\ \mathit{= \frac{45}{2}UNIT^2 }$



$IN \: \: CASE \: \: ( 2 ), \\ \\ \mathit{BASE = 10UNIT , \: \: HEIGHT = 6UNIT,} \\ \\ \mathit{AREA \: \: OF \: \: TRIANGLE = \frac{1}{2}(10 * 6)}\\ \\ \mathit{= 30UNIT^2 }$



$\mathit{NOW \: \: THE \: \: RATIO \: \: OF \: \: TRIANGLE = \frac{\frac{45}{2}}{30}}\\ \\ \mathit{= \frac{45}{2*30}}\\ \\ \mathit{= \frac{3}{4}} \\ \\ \mathit{HENCE, \: \: RATIO = 3:4}$
$\large{\mathbf{\underline{I \: \: HOPE \: \: ITS \: \: HELP \: \: YOU \: \: DEAR, THANKS}}}$