Question

Base of a triangle is 9 and height is 5. Base of another triangle is 10 and height is 6. Find the ratio of areas of these triangles​

Answer 1

Answer:

Heya !!

Here's your answer.. ⬇⬇

♦ Given :- Let The triangle be ∆ABC and ∆PQR.

In ∆ABC,

Base of ∆ABC is BC = 9cm

Altitude of ∆ABC is AE = 5cm

In ∆PQR,

Base is QR = 10cm

Altitude is PM = 6cm

♦ To Find :- Ratio of Area of ∆ABC and ∆PQR

♦ Solution :-

\begin{gathered} = \frac{area \: \: of \: \: abc}{area \: \: of \: \: pqr} \\ \\ = \frac{ \frac{1}{2} \times ae \times bc }{ \frac{1}{2} \times pm \times qr } \\ \\ = \frac{ \frac{1}{2} \times 5 \times 9 }{ \frac{1}{2} \times 6 \times 10} \\ \\ = \frac{3}{4} \\ \\ \end{gathered}

=

areaofpqr

areaofabc

=

2

1

×pm×qr

2

1

×ae×bc

=

2

1

×6×10

2

1

×5×9

=

4

3

Answer 2

Answer:

Answer by

Brainlyguru01

Trusted Helper

Brainly

Move to your question

To find your answer we have to first find the area of both triangle.

Area of triangle =1/2×base×height

So we call these triangle as triangle 1 and triangle 2

Triangle 1

Base of triangle 1 = 5

Height of triangle 1 = 9

Area of triangle 1 = 1/2× base × height

=1/2×5×9

= 45/2

=22.5

Triangle 2

Base of triangle 2 = 10

Height of Traingle 2 = 6

Area of Traingle 2 =1/2×base×height

=1/2×10×6

=30

So the ratio of both triangle is

22.5:30

Hope it may be helpful to you keep using brainly and keep studying