base of a triangle is 9 and height is 5 base of another triangle is 10 and height is 6 find the ratio of areas of these triangles
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Answer:
Let ABC and PQR be two right triangles with AB ⊥ BC and PQ ⊥ QR.
Given:
BC = 9, AB = 5, PQ = 6 and QR = 10.
∴A(△ABC)/A(△PQR)
=AB×BC/PQ×QR
=5×9/6×10
=3/4
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