base of a triangle is 9 and height is 5 base of another triangle is is 10 and height is 6 find the ratio of area of this Triangle
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the ratio of area ot two triangles is...
A1:A2=B1×H1:B2×H2
=9×5:10×6
=45:60
=3:4
i.e.the ratio of the given two triangles is
3:4.
hope it helps you....
A1:A2=B1×H1:B2×H2
=9×5:10×6
=45:60
=3:4
i.e.the ratio of the given two triangles is
3:4.
hope it helps you....
Answered by
1
Hey dear friend
1st ∆
Base=9cm
Height=5cm
Area of 1st∆=1/2*base*height
Area of 1st∆=1/2*9*5
Area of 1st∆=22.5cm²
2nd∆
Base of 2nd∆=10
Height of 2nd ∆=6
Area of 2nd∆=1/2*base*height
Area of 2nd ∆=1/2*10*6
Area of 2nd ∆=30cm²
Ratio of are of both the ∆
22.5cm² : 30cm²
1.5 : 2
Be PERFECTIONIST
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1st ∆
Base=9cm
Height=5cm
Area of 1st∆=1/2*base*height
Area of 1st∆=1/2*9*5
Area of 1st∆=22.5cm²
2nd∆
Base of 2nd∆=10
Height of 2nd ∆=6
Area of 2nd∆=1/2*base*height
Area of 2nd ∆=1/2*10*6
Area of 2nd ∆=30cm²
Ratio of are of both the ∆
22.5cm² : 30cm²
1.5 : 2
Be PERFECTIONIST
hope it helps you mark me as brainliest and follow me
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