base of a triangle is3 times its height if the area of the triangle is 300 cm ² find the length of its base and altitude
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Answer:
Step-by-step explanation:
let height = x cm
then base = 3x cm
area = 300 cm sq.
1/2 × b × h = 300
1/2 × 3x × x = 300
3x^2 / 2 = 300
3x^2 = 300 × 2
3x^2 = 600
x^2 = 600 / 3
x^2 = 200
x = √200 cm
height = x = √200 cm
base = 3x = 3√200 cm
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karankirat345:
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areaof triangle =1/2*base*height
base is 3 times =3x.
then. height is x
300=1/2*3x*x
300*2=3x^2
600 =3x^2
600/3=x^2
200=x^2
x=√200
height =√200
so base is 3x=3√200
hope it's it's help you
thanks.....
base is 3 times =3x.
then. height is x
300=1/2*3x*x
300*2=3x^2
600 =3x^2
600/3=x^2
200=x^2
x=√200
height =√200
so base is 3x=3√200
hope it's it's help you
thanks.....
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