base of an isosceles traingle is 24cm and its area is 192cm2, find perimtere?
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Step-by-step explanation:
The base of an isosceles triangle measures 24 cm and its area is 192cm2 , Find its perimeter. but area =192cm2[given ]. ⇒a2-144=256⇒a2=400⇒a=20.
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Given
- Base of isosceles triangle (b) = 24 cm
- Area of isosceles triangle (A) = 192 cm²
To find
- Perimeter (P)
Solution
- Area = ¼ × b √4a² - b²
- Area = ¼ × 24 × √4a² - 576
- Area = 12 × √a² - 144
- 192 = 12 × √a² - 144
- ¹⁹²⁄₁₂ = √a² - 144
- √a² - 144 = 16 (√ is transferred)
- a² - 144 = 256
- a² = 400
- a = √400
- a = 20
☯ We have, a and b, let's find Perimeter :
- Perimeter = 2a + b
- Perimeter = 2 × 20 + 24
- Perimeter = 64
☯ Perimeter of the isosceles triangle is 64 cm²
Anonymous:
Awesome! :)
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