base of an isosceles triangle measures 24 cm and its area is 60 square find its perimeter
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Step-by-step explanation:
area=60cm2
base=24cm
area=b÷4√4a^2-b^2
60=24÷4√4a^2-24^2
60÷6=√4a^2-576
squaring on both sides
100=4a^2-576
676=4a^2
a^2=169
a=13cm
perimeter = 2a+b
= (2×13)+24
=50cm
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