Question

Base of an issosceles triangle is 12cmand its equal sides is 10cm.Find its area.

Answer 1

Answer:

AB = 10cm

AC = 10cm

BC = 12cm

To find:

Area of isoceles triangle ABC

Solution:

s of triangle ABC = a+b+c/2

= 10 + 10 + 12/2

= 32/2

= 16cm

Now, using heron's formula,

Area of triangle ABC = √s(s-a)(s-b)(s-c)

= √16(16-10)(16-10)(16-12)

= √16(6)(6)(4)

= √ 2 x 2 x 2 x 2 x 3 x 2 x 3 x 2 x 2 x 2

= 48cm²

Answer 2

Step-by-step explanation:

Hope this is helpful to you please follow me up and mark my answer as brainlist ❤