base of isosceles triangle 3/2 times each of equal sides if its perimter is 28cm find area and height of the triangle
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let us assume equal sides to be a each and base=b
b=(3/2) a
28=a+a+b
= a+a+(3/2)a = (7/2)a
a=8, b= 12
apply heron's formula for area
for height drop perpendicular on base and then Pythagoras theorem
area= 12√7
height= 2√7
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