Question

Base of isosceles triangle is 4/3 cm. the perimeter of the triangle is 4 and 2/5cm. what is the length of either of the remaining equal sides?​

Answer 1

Answer:

Let the length of equal sides be x cm. Perimeter = x cm + x cm + Base = 4 2/15 cm 2x + 4/3 = 62/15 On transposing 4/3 to R.H.S, we obtain 2x = 62/15 - 4/3 2x = 62 - 4 x 5/15 = 62 - 20/15 2x = 42/15 On dividing both sides by 2, we obtain 2x/2 = 42/15 x1/2 x = 7/5 = 1 2/5 Therefore, the length of equal sides is 1 2/5 c m