Question

base of one triangle is 5 unit and height is 7 and base of another triangleis 6 and height is also 6​

Answer 1

Answer:

what we should find out?

Answer 2

Answer:

Heya !!

Here's your answer.. ⬇⬇

♦ Given :- Let The triangle be ∆ABC and ∆PQR.

In ∆ABC,

Base of ∆ABC is BC = 9cm

Altitude of ∆ABC is AE = 5cm

In ∆PQR,

Base is QR = 10cm

Altitude is PM = 6cm

♦ To Find :- Ratio of Area of ∆ABC and ∆PQR

♦ Solution :- 

\begin{gathered} = \frac{area \: \: of \: \: abc}{area \: \: of \: \: pqr} \\ \\ = \frac{ \frac{1}{2} \times ae \times bc }{ \frac{1}{2} \times pm \times qr } \\ \\ = \frac{ \frac{1}{2} \times 5 \times 9 }{ \frac{1}{2} \times 6 \times 10} \\ \\ = \frac{3}{4} \\ \\ \end{gathered}=areaofpqrareaofabc=21×pm×qr21×ae×bc=21×6×1021×5×9=43 

Hence, Ratio of Area of ∆ABC to ∆PQR is 3:4

Hope it helps..

Thanks. (: