Question

Base of the isosceles triangle is 10 cm And measure of two equal side is 15 cm. Than find area of triangle.​

Answer 1

A n s w e r

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G i v e n

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• Base of the isosceles triangle is 10 cm

• Other two equal side is 15 cm

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F i n d

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• Area of triangle

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S o l u t i o n

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We know that ,

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$\underline{ \underline{\bold{\texttt{Area of triangle :}}}}$

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➠ $\sf \sqrt { s(s - a)(s - b)(s -c) }$ ⚊⚊⚊⚊ ⓵

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Where ,

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• a = First side of triangle

• b = Second side of triangle

• c = Third side of triangle

• s = Semi perimeter

• $\sf s = \dfrac { a + b + c } { 2 }$

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$\underline{ \underline{\bold{\texttt{For the given triangle :}}}}$

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• a = 10 cm

• b = 15 cm

• c = 15 cm

• $\sf s = \dfrac { 10 + 15 + 15} { 2 } = \dfrac { 40 } { 2 } = 20 \: cm$

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⟮ Putting the above values in ⓵ ⟯

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: ➜ $\sf \sqrt { s(s - a)(s - b)(s -c) }$

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: ➜ $\sf \sqrt { 20(20 - 10)(20 - 15)(20 - 15) }$

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: ➜ $\sf \sqrt { 20(10)(5)(5) }$

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: ➜ $\sf \sqrt { (200)(5)(5) }$

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: ➜ $\sf \sqrt { (2 \times 2 \times 2 \times 5 \times 5)(5)(5) }$

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: ➜ $\sf 2 \times 5 \times 5 \sqrt 2$

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: ➜ $\sf 50\sqrt 2$

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: : ➨ 70.71 sq. cm

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• Hence the area of the given isosceles triangle is 70.71 sq. cm

Answer 2

Answer:

I don't know but you can do it