Question

Base of triangle is 10 and height is 7. Base of another

triangle is 9.and height is 6. Find ratio of area of these

triangles.

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Answer 1

Answer:

this answer is there of G00gle

Answer 2

Given : Base of triangle is 10cm and height is 7cm and Base of another triangle is 9cm and height is 6cm.

Excise To Find : The ratio of area of these triangles.

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❒ Let's consider Base of one Triangle as b¹ , Height of one triangle as h² and Base of another triangle as b² and Height of another triangle as h² .

$\underline {\frak{ As,\:We \:Know \:that \::}}$

⠀⠀⠀⠀⠀ $\implies {\boxed {\sf{ Area _{(Triangle)} = \dfrac{1}{2} \times b \times h \: .}}}$

⠀⠀⠀⠀⠀ Here b is the Base of Triangle in cm and h is the Height of Triangle in cm .

Then ,

• Their ratios of their Area are :

⠀⠀⠀⠀⠀ $\implies {\boxed {\sf{ \dfrac{Area _{(Triangle)} \:1}{Area\:_{(Triangle)}\:2} =\dfrac{ \dfrac{1}{2} \times b_{1} \times h_{1} }{\dfrac{1}{2} \times b_{2} \times h_{2}} \: .}}}$

⠀⠀⠀⠀⠀⠀$\underline {\frak{\star\:Now \: By \: Substituting \: the \: Given \: Values \::}}$

⠀⠀⠀⠀⠀ $:\implies {\sf{ \dfrac{Area \:of\triangle \:\:1}{Area\:of\:\triangle \:2} =\dfrac{ \dfrac{1}{2} \times 10 \times 7 }{\dfrac{1}{2} \times 9 \times 6 } \: .}}$

⠀⠀⠀⠀⠀ $:\implies {\sf{ \dfrac{Area \:of\triangle \:\:1}{Area\:of\:\triangle \:2} =\dfrac{ \dfrac{1}{\cancel {2}} \times \cancel {10} \times 7 }{\dfrac{1}{\cancel {2}} \times 9 \times \cancel {6} } \: .}}$

⠀⠀⠀⠀⠀ $:\implies {\sf{ \dfrac{Area \:of\triangle \:\:1}{Area\:of\:\triangle \:2} =\dfrac{ 5 \times 7 }{ 9 \times 3 } \: .}}$

⠀⠀⠀⠀⠀ $:\implies {\sf{ \dfrac{Area \:of\triangle \:\:1}{Area\:of\:\triangle \:2} =\dfrac{ 35 }{ 27 } \: .}}$

Therefore,

⠀⠀⠀⠀⠀$\underline {\therefore\:{ \mathrm {  Hence,\: The\:Ratio\:of\:area\:of\:both\:triangle \:are\:35:27}}}$

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