Base of triangle is 9 and height is 5. Base of another triangle is 20 and height is 6. Find the ratio of areas of these triangle.
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♦ Given :- Let The triangle be ∆ABC and ∆PQR.
In ∆ABC,
Base of ∆ABC is BC = 9cm
Altitude of ∆ABC is AE = 5cm
In ∆PQR,
Base is QR = 10cm
Altitude is PM = 6cm
♦ To Find :- Ratio of Area of ∆ABC and ∆PQR
Area of ∆ ABC = (base × height)/2
Area of ∆ ABC =(9×5)/2
Area of ∆ ABC = 45/2 = 22.5 unit²
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Area of ∆ PQR = (10×6)/2
Area of ∆ PQR = 10×3=30 unit²
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Ratio = 22.5 : 30
Ratio= 225:300
Ratio = 3:4
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