Question

base of triangle is 9 and height is 5.base of another triangle is 10 and height is 6.find the ratio of areas of the triangle​

Answer 1

Area of 1st ∆

= 1/2 x base x height

= 1/2 x 9 x 5

Area of 2nd ∆

= 1/2 x base x height

= 1/2 x 10 x 6

Ratio of their area =

$\frac{ \frac{1}{2} \times 9 \times 5 } { \frac{1}{2} \times 10 \times 6 }$

=

$\frac{3}{4}$

Ratio = 3 : 4

Answer 2

Answer:

Let ABC and PQR be two right triangles with AB ⊥ BC and PQ ⊥ QR.

Given:

BC = 9, AB = 5, PQ = 6 and QR = 10.

∴A(△ABC)/A(△PQR)

=AB×BC/PQ×QR

=5×9/6×10

=3/4