Question

Base of triangle is 9 and height is 5 . Best of another triangle is 10 and hight e6. Find the radius of area of these triangle

Answer 1

Heya !!

Here's your answer.. ⬇⬇

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»Given :- Let The triangle be ∆ABC and ∆PQR.

In ∆ABC,

Base of ∆ABC is BC = 9cm

Altitude of ∆ABC is AE = 5cm

In ∆PQR,

Base is QR = 10cm

Altitude is PM = 6cm

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»To Find :- Ratio of Area of ∆ABC and ∆PQR

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» Solution :-

$\begin{lgathered}= \frac{area \: \: of \: \: abc}{area \: \: of \: \: pqr} = \frac{ \frac{1}{2} \times ae \times bc }{ \frac{1}{2} \times pm \times qr } = \frac{ \frac{1}{2} \times 5 \times 9 }{ \frac{1}{2} \times 6 \times 10} = \frac{3}{4} end{lgathered}$

Hence, Ratio of Area of ∆ABC to ∆PQR is 3:4

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Hope it helps..

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