Question

base of triangle is 9,height is 4, base of another triangle is 18 and height is 3 then what is the ratio of their areas​

Answer 1

Answer:

Base of first trangle=b1= 9 units.

Height=h1=4 units.

Therefore, Area of first triangle,

$a1 = \frac{1}{2} \times b1 \times h1$

$a1 = \frac{1}{2} \times 9 \times 4$

$a1 = 18 \: {unit}^{2}$

Base of second triangle=b2= 18 units.

Height=h1= 3 units.

Therefore, Area of second triangle,

$a2 = \frac{1}{2 } \times b2 \times h2$

$a2 = \frac{1}{2} \times 18 \times 3$

$a2 = 27 \: {unit}^{2}$

Ratio of areas= a1:a2= 18:27= 2:3.

ANS. Ratio of areas of two triangles is 2:3