Base of triangles is 9 and height is 5 .base of another triangles os 10 and height is 6 . Find the ratio of areas of these triangles.
Answers
Answered by
15
Answer:
3:4
Step-by-step explanation:
Given:
- Base of the first triangle = 9
- Height of the first triangle = 5
- Base of the second triangle = 10
- Height of the second triangle = 6
To find:
- Ratio of the areas of these triangles
Area of a traingle = 1/2×b×h
Area of the first triangle = 1/2×9×5
Area of the first triangle = 4.5×5
Area of the first triangle = 22.5
Area of the second triangle = 1/2×10×6
Area of the second triangle = 5×6
Area of the second triangle = 30
Ratio of area of first triangle to ratio of area of second triangle = 22.5:30
Ratio of area of first triangle to ratio of area of second triangle = 3:4
the ratio is 3:4
Answered by
42
Method 1 (solve individually):
Area of a triangle= 1/2 x base x height
Area of 1st triangle= 1/2 x 9 x 5 = 22.5
Area of 2nd triangle= 1/2 x 10 x 6 = 30
22.5 : 30
2(22.5) : 2(30) —> multiplying both sides by two since ration has to be in whole numbers.
=45:60
(45)/15 :(60)/15 —> dividing both sides by 15 to get the simplest ratio
3:4
Method 2 (solve together):
1/2 x 9 x 5 : 1/2 x 10 x 6
= 9 x 5 : 10 x 6 (half and half get cut)
= 45/15 : 60/15
= 3:4
Area of a triangle= 1/2 x base x height
Area of 1st triangle= 1/2 x 9 x 5 = 22.5
Area of 2nd triangle= 1/2 x 10 x 6 = 30
22.5 : 30
2(22.5) : 2(30) —> multiplying both sides by two since ration has to be in whole numbers.
=45:60
(45)/15 :(60)/15 —> dividing both sides by 15 to get the simplest ratio
3:4
Method 2 (solve together):
1/2 x 9 x 5 : 1/2 x 10 x 6
= 9 x 5 : 10 x 6 (half and half get cut)
= 45/15 : 60/15
= 3:4
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