base pairs 500 and adenine contain 20% then total no of hydrogen bonds present is
Answers
Explanation:
In double stranded DNA, purines (Adenine and Guanine) pair with pyrimidines (Thymine and Cytosine).
In double stranded DNA, purines (Adenine and Guanine) pair with pyrimidines (Thymine and Cytosine).Adenine (A) pairs with Thymine (T) with two hydrogen bonds and Guanine (G) pairs with Cytosine (C) with three hydrogen bonds.
In double stranded DNA, purines (Adenine and Guanine) pair with pyrimidines (Thymine and Cytosine).Adenine (A) pairs with Thymine (T) with two hydrogen bonds and Guanine (G) pairs with Cytosine (C) with three hydrogen bonds.Thus, amount of A is equal to T and amount of G is equal to C
In double stranded DNA, purines (Adenine and Guanine) pair with pyrimidines (Thymine and Cytosine).Adenine (A) pairs with Thymine (T) with two hydrogen bonds and Guanine (G) pairs with Cytosine (C) with three hydrogen bonds.Thus, amount of A is equal to T and amount of G is equal to C(i) So, out of 100 base pairs, if 40 are G, then C will also be 40
In double stranded DNA, purines (Adenine and Guanine) pair with pyrimidines (Thymine and Cytosine).Adenine (A) pairs with Thymine (T) with two hydrogen bonds and Guanine (G) pairs with Cytosine (C) with three hydrogen bonds.Thus, amount of A is equal to T and amount of G is equal to C(i) So, out of 100 base pairs, if 40 are G, then C will also be 40As (A + T) + (G+C) = 100, so A + T = 100 - (40 + 40) = 100 - 80 = 20
In double stranded DNA, purines (Adenine and Guanine) pair with pyrimidines (Thymine and Cytosine).Adenine (A) pairs with Thymine (T) with two hydrogen bonds and Guanine (G) pairs with Cytosine (C) with three hydrogen bonds.Thus, amount of A is equal to T and amount of G is equal to C(i) So, out of 100 base pairs, if 40 are G, then C will also be 40As (A + T) + (G+C) = 100, so A + T = 100 - (40 + 40) = 100 - 80 = 20and A = T = 20/2 = 10
In double stranded DNA, purines (Adenine and Guanine) pair with pyrimidines (Thymine and Cytosine).Adenine (A) pairs with Thymine (T) with two hydrogen bonds and Guanine (G) pairs with Cytosine (C) with three hydrogen bonds.Thus, amount of A is equal to T and amount of G is equal to C(i) So, out of 100 base pairs, if 40 are G, then C will also be 40As (A + T) + (G+C) = 100, so A + T = 100 - (40 + 40) = 100 - 80 = 20and A = T = 20/2 = 10So, nucleotides having A are 10 and nucleotides having C are 40
In double stranded DNA, purines (Adenine and Guanine) pair with pyrimidines (Thymine and Cytosine).Adenine (A) pairs with Thymine (T) with two hydrogen bonds and Guanine (G) pairs with Cytosine (C) with three hydrogen bonds.Thus, amount of A is equal to T and amount of G is equal to C(i) So, out of 100 base pairs, if 40 are G, then C will also be 40As (A + T) + (G+C) = 100, so A + T = 100 - (40 + 40) = 100 - 80 = 20and A = T = 20/2 = 10So, nucleotides having A are 10 and nucleotides having C are 40(ii) In this DNA, base pairs G and C are maximum as they are present in 40 nucleotides.
Answer:
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Explanation:
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