Computer Science, asked by dlnprasunna, 9 months ago

Based on a survey, it was found that the probability that a student likes to play football was 0.25 and the probability that a student likes
to play cricket is 0.43. It was also found that the probability that a student likes to play both football and cricket is 0.12. What is the
probability that a student does not like to play either?
0.32
0.2
0.44
0.56

Answers

Answered by zoya0710
3

Explanation:

P (student like football)=0.25

P (students like cricket)=0.43

P (like both)=0.12

P (does not like either)=1 - (0.25+0.43+0.12)

=1 - 0.8

=0.2

HOPE IT WILL HELP YOU

Answered by nayanpaul24
4

Answer:

Answer is  0.44

Explanation:

Given P(football) = 0.25, P(cricket) = 0.43, and P(football ∩ cricket) = 0.12.

We are interested in the probability of students who do not like to play either football or cricket, i.e., P( (football ∪ cricket)' ).

From basic set theory, we have P(football ∪ cricket) = P(football) + P(cricket) - P(football ∩ cricket) = 0.25 + 0.43 - 0.12 = 0.56.

Also, the two events, a student likes to play football or cricket                (football ∪ cricket) and a student does not like to play either football or cricket ((football ∪ cricket)' ) are mutually exclusive.

Therefore, we have P((football ∪ cricket)' ) = 1 - P(football ∪ cricket)

                                                                      = 1 - 0.56 = 0.44 (Answer)

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