Based on the following data for a reaction what is its order (A - products)
Conc. A 2M 0.2M 0.02M 0.00
Time in min. 0 10 20 infinite
1. 1
st 2. 2
nd 3. 3
rd 4. zero
Answers
Explanation:
ANSWER
ANSWERFor first order reaction,
ANSWERFor first order reaction,A⟶B
ANSWERFor first order reaction,A⟶BRate =k×[A]
ANSWERFor first order reaction,A⟶BRate =k×[A]Given, rate =2.0×10−5molL−1s−1
ANSWERFor first order reaction,A⟶BRate =k×[A]Given, rate =2.0×10−5molL−1s−1[A] = Conc. of A = 0.01 M
ANSWERFor first order reaction,A⟶BRate =k×[A]Given, rate =2.0×10−5molL−1s−1[A] = Conc. of A = 0.01 M So, 2.0×10−5=k×0.01
ANSWERFor first order reaction,A⟶BRate =k×[A]Given, rate =2.0×10−5molL−1s−1[A] = Conc. of A = 0.01 M So, 2.0×10−5=k×0.01k=0.012.0×10−5s−1
ANSWERFor first order reaction,A⟶BRate =k×[A]Given, rate =2.0×10−5molL−1s−1[A] = Conc. of A = 0.01 M So, 2.0×10−5=k×0.01k=0.012.0×10−5s−1 =2.0×10−3s−1
ANSWERFor first order reaction,A⟶BRate =k×[A]Given, rate =2.0×10−5molL−1s−1[A] = Conc. of A = 0.01 M So, 2.0×10−5=k×0.01k=0.012.0×10−5s−1 =2.0×10−3s−1For first order reaction,
ANSWERFor first order reaction,A⟶BRate =k×[A]Given, rate =2.0×10−5molL−1s−1[A] = Conc. of A = 0.01 M So, 2.0×10−5=k×0.01k=0.012.0×10−5s−1 =2.0×10−3s−1For first order reaction,t1/2=k0.693=2.0×10−30.693
ANSWERFor first order reaction,A⟶BRate =k×[A]Given, rate =2.0×10−5molL−1s−1[A] = Conc. of A = 0.01 M So, 2.0×10−5=k×0.01k=0.012.0×10−5s−1 =2.0×10−3s−1For first order reaction,t1/2=k0.693=2.0×10−30.693=346.5=347s
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