Question

Based on the mathematical rule, Find out a five digit number which completly divisible by "9" from 86325


I hope any one in hate who can help me to get answer​

Answer 1

Five digit number which completely divisible by "9" from 86325​  is 86328

Step-by-step explanation:

Divisibility rule of 9 is that

sum of digits of number is divisible by 9

86325

= 8 + 6 + 3 + 2 + 5

= 24

24

= 2 + 4

= 6

Remainder = 6

so to make it divisible by 9 we need to add 9  - 6  = 3

86325 + 3

= 86328

86328 would be Divisible by 9

86328/9 = 9592

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Answer 2

The required number is 86328.

Step-by-step explanation:

To find : A five digit number which completely divisible by "9" from 86325  ?

Solution :

The divisibility rule of 9 states that sum of digits of number is divisible by 9.

i.e. 86325 = 8 + 6 + 3 + 2 + 5 = 24

24 is not divisible by 9

So, 2+4=6 the remainder is 6

Now to make it divisible by 9,

We need to add 9 - 6  = 3

i.e. 86325 + 3 = 86328

Now, 86328 =8 + 6 + 3 + 2 + 8=27

27 is divisible by 9.

Therefore, the required number is 86328.

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