Based on valence electrons, what would the charge of Oxygen be?
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take this example further. Oxygen in alcohol, R−O−H , "owns" 6 valence electrons, and is neutral. Oxygen in alkoxide (or hydroxide), "owns" 7 valence electrons, and is therefore formally represented as R−O− , with the negative charge localized on the oxygen atom (3 lone pairs + 1 electron from the C−O bond).
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