Based on VSEPR theory how many 90 degrees F-Br-F angles in BrF5
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from the VSEPR theory the no of electron around Br atom is 6 - five are bond and one is lone pair so geometry is octahedral. but it have one lone pair which repuls the other and so florine of corner are forsed to upper florine and reduce the angle F-Br-F and make 84.8°. so no any F-Br-F bond form 90°
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